What is (x^2-9)/(x^4-81) ?

The solution to (x^2-9)/(x^4-81) is 1/(x^2+9)

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simplify (x^2-9)/(x^4-81)

simplify

\frac{x ^{2} - 9}{x ^{4} - 81}

\frac{1}{x ^{2} + 9}

Solution steps

\frac{x ^{2} - 9}{x ^{4} - 81}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{4} - 81}

Factor

x^{4} - 81 : (x^{2} + 9) (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{( x ^{2} + 9 ) ( x + 3 ) ( x - 3 )}

Cancel the common factor:

x + 3

= \frac{x - 3}{( x ^{2} + 9 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{1}{x ^{2} + 9}

lo g_{2} (0.4)

\frac{0}{16}

\frac{128}{7}

(x + 3) (x + 3) (x + 3)

lo g_{10} (lo g_{10} (1 0^{100000}))