What is 1+(2b)/3+(b^2)/9 ?

The solution to 1+(2b)/3+(b^2)/9 is (9+6b+b^2)/9

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simplify 1+(2b)/3+(b^2)/9

simplify

1 + \frac{2 b}{3} + \frac{b ^{2}}{9}

\frac{9 + 6 b + b ^{2}}{9}

Solution steps

1 + \frac{2 b}{3} + \frac{b ^{2}}{9}

Join

\frac{2 b}{3} + \frac{b ^{2}}{9} : \frac{6 b + b ^{2}}{9}

= 1 + \frac{6 b + b ^{2}}{9}

Apply the fraction rule:

1 + \frac{b}{c} = \frac{c + b}{c}

= \frac{9 + 6 b + b ^{2}}{9}

\frac{15 a ^{3} b ^{2}}{20 a b ^{4}}

t^{2} \cdot t^{3}

- 9 - 32

0 + 5

7 + 3