What is the extreme I(P,t)=(Pt)/(100) ?

The extreme I(P,t)=(Pt)/(100) is Saddle(0,0)

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extreme I(P,t)=(Pt)/(100)

extreme points

I (P, t) = \frac{Pt}{100}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial P ^{2}} = 0

D (P, t) = - \frac{1}{10000}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

(- \frac{3}{5})^{0}

\frac{8 x + 7}{6} \leq \frac{5 x + 2}{7}

49 x^{2} - 100 y^{4}

x^{2} + x^{2} = 2

- 3 x^{2} = - 363

What is the extreme I(P,t)=(Pt)/(100) ?
The extreme I(P,t)=(Pt)/(100) is Saddle(0,0)