What is (6+i)-3i(2-i) ?

The solution to (6+i)-3i(2-i) is 3-5i

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simplify (6+i)-3i(2-i)

simplify

(6 + i) - 3 i (2 - i)

3 - 5 i

Solution steps

(6 + i) - 3 i (2 - i)

Apply rule:

(a) = a

(6 + i) = 6 + i

= 6 + i - 3 i (2 - i)

Expand

- 3 i (2 - i) : - 6 i - 3

= 6 + i - 6 i - 3

Group like terms

= i - 6 i + 6 - 3

Add similar elements:

i - 6 i = - 5 i

= - 5 i + 6 - 3

Subtract the numbers:

6 - 3 = 3

= - 5 i + 3

Rewrite in standard complex form:

3 - 5 i

= 3 - 5 i

\frac{( x ^{3} + 1 )}{( x + 1 )}

\frac{x ^{3} - 2 x ^{2} - 5 x - 12}{x - 4}

\frac{( \frac{1}{5} ) ^{4} \cdot ( \frac{1}{5} ) ^{- 2}}{5 ^{6}}

(3 sin (x))^{2}

\frac{x ^{2} - 5 x + 6}{x ^{2} + 2 x - 15}