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Popular >

expand (1-y^2)^3

Solution

expand

(1 - y^{2})^{3}

Solution

1 - 3 y^{2} + 3 y^{4} - y^{6}

Solution steps

(1 - y^{2})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(1 - y^{2})^{3} = 1^{3} - 3 \cdot 1^{2} y^{2} + 3 \cdot 1 \cdot (y^{2})^{2} - (y^{2})^{3}

= 1^{3} - 3 \cdot 1^{2} y^{2} + 3 \cdot 1 \cdot (y^{2})^{2} - (y^{2})^{3}

Simplify

1^{3} - 3 \cdot 1^{2} y^{2} + 3 \cdot 1 \cdot (y^{2})^{2} - (y^{2})^{3} : 1 - 3 y^{2} + 3 y^{4} - y^{6}

= 1 - 3 y^{2} + 3 y^{4} - y^{6}

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Frequently Asked Questions (FAQ)

What is expand (1-y^2)^3 ?
The solution to expand (1-y^2)^3 is 1-3y^2+3y^4-y^6