What is (x^2)/(x^2-4)-(x+1)/(x+2) ?

The solution to (x^2)/(x^2-4)-(x+1)/(x+2) is 1/(x-2)

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simplify (x^2)/(x^2-4)-(x+1)/(x+2)

simplify

\frac{x ^{2}}{x ^{2} - 4} - \frac{x + 1}{x + 2}

\frac{1}{x - 2}

Solution steps

\frac{x ^{2}}{x ^{2} - 4} - \frac{x + 1}{x + 2}

Least Common Multiplier of

x^{2} - 4, x + 2 : (x + 2) (x - 2)

Adjust Fractions based on the LCM

= \frac{x ^{2}}{( x + 2 ) ( x - 2 )} - \frac{( x + 1 ) ( x - 2 )}{( x + 2 ) ( x - 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x ^{2} - ( x + 1 ) ( x - 2 )}{( x + 2 ) ( x - 2 )}

Simplify

x^{2} - (x + 1) (x - 2) : x + 2

= \frac{x + 2}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x + 2

= \frac{1}{x - 2}

- 4 \times (- 3)

\frac{5 x ^{3}}{15 x ^{4} - 15 x ^{3}}

(4 - 72) (- 4 - 64)

lo g_{15} (87.5)

\frac{3 p - 4 q}{4 q - 3 p}

What is (x^2)/(x^2-4)-(x+1)/(x+2) ?
The solution to (x^2)/(x^2-4)-(x+1)/(x+2) is 1/(x-2)