What is ((6pq)/4)/(\frac{q^2){12}} ?

The solution to ((6pq)/4)/(\frac{q^2){12}} is (18p)/q

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simplify ((6pq)/4)/(\frac{q^2){12}}

simplify

\frac{\frac{6 pq}{4}}{\frac{q ^{2}}{12}}

\frac{18 p}{q}

Solution steps

\frac{\frac{6 pq}{4}}{\frac{q ^{2}}{12}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{6 pq \cdot 12}{4 q ^{2}}

Cancel

\frac{6 pq \cdot 12}{4 q ^{2}} : \frac{18 p}{q}

= \frac{18 p}{q}

\frac{- 3 x ^{2} y ^{5} z ^{2}}{x ^{- 2} y ^{2} z}

3 x \cdot 4 x

\frac{1}{1 \cdot 1 0 ^{6}}

\frac{1}{x + 4} + \frac{7}{x}

lo g_{2} (\frac{1}{2 ^{2}})

What is ((6pq)/4)/(\frac{q^2){12}} ?
The solution to ((6pq)/4)/(\frac{q^2){12}} is (18p)/q