What is (y^2+3y+2)/(y^2-1) ?

The solution to (y^2+3y+2)/(y^2-1) is (y+2)/(y-1)

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simplify (y^2+3y+2)/(y^2-1)

simplify

\frac{y ^{2} + 3 y + 2}{y ^{2} - 1}

\frac{y + 2}{y - 1}

Solution steps

\frac{y ^{2} + 3 y + 2}{y ^{2} - 1}

Factor

y^{2} + 3 y + 2 : (y + 1) (y + 2)

= \frac{( y + 1 ) ( y + 2 )}{y ^{2} - 1}

Factor

y^{2} - 1 : (y + 1) (y - 1)

= \frac{( y + 1 ) ( y + 2 )}{( y + 1 ) ( y - 1 )}

Cancel the common factor:

y + 1

= \frac{y + 2}{y - 1}

(3 a - 2)^{2}

\frac{( 3 + \frac{1}{2 x - 1} )}{( 5 + \frac{x}{2 x - 1} )}

\frac{3 d ^{2}}{5}

\frac{2 - i}{1 + 2 i}

32 + 2