What is (x^2-4x-5)/(x^2-2x-15)*(7x)/(7x) ?

The solution to (x^2-4x-5)/(x^2-2x-15)*(7x)/(7x) is (x+1)/(x+3)

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simplify (x^2-4x-5)/(x^2-2x-15)*(7x)/(7x)

simplify

\frac{x ^{2} - 4 x - 5}{x ^{2} - 2 x - 15} \cdot \frac{7 x}{7 x}

\frac{x + 1}{x + 3}

Solution steps

\frac{x ^{2} - 4 x - 5}{x ^{2} - 2 x - 15} \cdot \frac{7 x}{7 x}

Cancel

\frac{x ^{2} - 4 x - 5}{x ^{2} - 2 x - 15} : \frac{x + 1}{x + 3}

= \frac{x + 1}{x + 3} \cdot \frac{7 x}{7 x}

Apply the fraction rule:

\frac{a}{a} = 1

\frac{7 x}{7 x} = 1

= \frac{x + 1}{x + 3} \cdot 1

Apply rule:

a \cdot 1 = a

= \frac{x + 1}{x + 3}

3 + \frac{3}{2}

(2 n^{4})^{3}

x^{3} - 3 x^{2} + 3 x

\frac{4 x ^{2} - 9}{8 x ^{3} - 27}

(i^{11} + i^{- 5})^{6}

What is (x^2-4x-5)/(x^2-2x-15)*(7x)/(7x) ?
The solution to (x^2-4x-5)/(x^2-2x-15)*(7x)/(7x) is (x+1)/(x+3)