What is log_{2}(28)+log_{2}(6)-log_{2}(21) ?

The solution to log_{2}(28)+log_{2}(6)-log_{2}(21) is 3

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simplify log_{2}(28)+log_{2}(6)-log_{2}(21)

simplify

lo g_{2} (28) + lo g_{2} (6) - lo g_{2} (21)

3

Solution steps

lo g_{2} (28) + lo g_{2} (6) - lo g_{2} (21)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (28) + lo g_{2} (6) = lo g_{2} (28 \cdot 6)

= lo g_{2} (28 \cdot 6) - lo g_{2} (21)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (28 \cdot 6) - lo g_{2} (21) = lo g_{2} (\frac{28 \cdot 6}{21})

= lo g_{2} (\frac{28 \cdot 6}{21})

\frac{28 \cdot 6}{21} = 2^{3}

= lo g_{2} (2^{3})

Apply log rule:

lo g_{a} (a^{b}) = b

= 3

\frac{10 - 6 i}{6 + 5 i}

925

- 7 - (- 8)

- lo g_{10} (0.002)

lo g_{\frac{1}{8}} (8)

What is log_{2}(28)+log_{2}(6)-log_{2}(21) ?
The solution to log_{2}(28)+log_{2}(6)-log_{2}(21) is 3