What is (10y^2+15y)/(35y^2-5y) ?

The solution to (10y^2+15y)/(35y^2-5y) is (2y+3)/(7y-1)

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simplify (10y^2+15y)/(35y^2-5y)

simplify

\frac{10 y ^{2} + 15 y}{35 y ^{2} - 5 y}

\frac{2 y + 3}{7 y - 1}

Solution steps

\frac{10 y ^{2} + 15 y}{35 y ^{2} - 5 y}

Factor

10 y^{2} + 15 y : 5 y (2 y + 3)

= \frac{5 y ( 2 y + 3 )}{35 y ^{2} - 5 y}

Factor

35 y^{2} - 5 y : 5 y (7 y - 1)

= \frac{5 y ( 2 y + 3 )}{5 y ( 7 y - 1 )}

Cancel the common factor:

5

= \frac{y ( 2 y + 3 )}{y ( 7 y - 1 )}

Cancel the common factor:

y

= \frac{2 y + 3}{7 y - 1}

\frac{2}{7} + \frac{1}{3}

(x - 3 y)^{5}

lo g_{8} (lo g_{14} (196) - lo g_{7} (7))

7 (- 1 + 9 i)

- 3 (x - 4)

What is (10y^2+15y)/(35y^2-5y) ?
The solution to (10y^2+15y)/(35y^2-5y) is (2y+3)/(7y-1)