What is (4x^2-x)/(16x^2-1) ?

The solution to (4x^2-x)/(16x^2-1) is x/(4x+1)

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simplify (4x^2-x)/(16x^2-1)

simplify

\frac{4 x ^{2} - x}{16 x ^{2} - 1}

\frac{x}{4 x + 1}

Solution steps

\frac{4 x ^{2} - x}{16 x ^{2} - 1}

Factor

4 x^{2} - x : x (4 x - 1)

= \frac{x ( 4 x - 1 )}{16 x ^{2} - 1}

Factor

16 x^{2} - 1 : (4 x + 1) (4 x - 1)

= \frac{x ( 4 x - 1 )}{( 4 x + 1 ) ( 4 x - 1 )}

Cancel the common factor:

4 x - 1

= \frac{x}{4 x + 1}

7 \frac{2}{9} - 3 \frac{5}{6}

25 - (10 + 7) - 50 + 7^{2}

- 256

\frac{30}{48}

\frac{30}{72}