What is (\frac{x^3-x)/(3x-6)}{(5x+5)/(2x-4)} ?

The solution to (\frac{x^3-x)/(3x-6)}{(5x+5)/(2x-4)} is (2x(x-1))/(15)

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simplify (\frac{x^3-x)/(3x-6)}{(5x+5)/(2x-4)}

simplify

\frac{\frac{x ^{3} - x}{3 x - 6}}{\frac{5 x + 5}{2 x - 4}}

\frac{2 x ( x - 1 )}{15}

Solution steps

\frac{\frac{x ^{3} - x}{3 x - 6}}{\frac{5 x + 5}{2 x - 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{3} - x ) ( 2 x - 4 )}{( 3 x - 6 ) ( 5 x + 5 )}

Cancel

\frac{( x ^{3} - x ) ( 2 x - 4 )}{( 3 x - 6 ) ( 5 x + 5 )} : \frac{x ( x - 1 ) \cdot 2}{15}

= \frac{x ( x - 1 ) \cdot 2}{15}

= \frac{2 x ( x - 1 )}{15}

2 - 108

n - 4 - 9

\frac{- 7}{3} - \frac{4}{6} + \frac{- 5}{7} - \frac{- 6}{4}

x^{3} \times x^{2}

sin (2 x) + sin (2 x)

What is (\frac{x^3-x)/(3x-6)}{(5x+5)/(2x-4)} ?
The solution to (\frac{x^3-x)/(3x-6)}{(5x+5)/(2x-4)} is (2x(x-1))/(15)