What is log_{10}(40)+log_{10}(25) ?

The solution to log_{10}(40)+log_{10}(25) is 3

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simplify log_{10}(40)+log_{10}(25)

simplify

lo g_{10} (40) + lo g_{10} (25)

3

Solution steps

lo g_{10} (40) + lo g_{10} (25)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (40) + lo g_{10} (25) = lo g_{10} (40 \cdot 25)

= lo g_{10} (40 \cdot 25)

Multiply the numbers:

40 \cdot 25 = 1000

= lo g_{10} (1000)

Factor the number:

1000 = 1 0^{3}

= lo g_{10} (1 0^{3})

Apply log rule:

lo g_{a} (a^{b}) = b

= 3

\frac{x ^{2} - 4}{x ^{2} + 6 x + 8} \cdot \frac{9 x + 36}{x - 8}

(2 x^{2} y^{4})^{5}

5 (- 3 p + 7) + 5 (p - 1)

8 \div \frac{5}{6}

\frac{3 x ^{2} - 2}{3 x - 2} - \frac{x}{2 - 3 x}

What is log_{10}(40)+log_{10}(25) ?
The solution to log_{10}(40)+log_{10}(25) is 3