What is (-9+5i)/(3-i) ?

The solution to (-9+5i)/(3-i) is -16/5+3/5 i

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simplify (-9+5i)/(3-i)

simplify

\frac{- 9 + 5 i}{3 - i}

- \frac{16}{5} + \frac{3}{5} i

Solution steps

\frac{- 9 + 5 i}{3 - i}

Multiply by the conjugate

\frac{3 + i}{3 + i}

= \frac{( - 9 + 5 i ) ( 3 + i )}{( 3 - i ) ( 3 + i )}

Simplify

\frac{( - 9 + 5 i ) ( 3 + i )}{( 3 - i ) ( 3 + i )} : \frac{- 32 + 6 i}{10}

= \frac{- 32 + 6 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 32}{10} + \frac{6}{10} i

Simplify

\frac{- 32}{10} + \frac{6}{10} i : - \frac{16}{5} + \frac{3}{5} i

= - \frac{16}{5} + \frac{3}{5} i

\frac{5}{6} + \frac{1}{3} \cdot \frac{1}{2}

\frac{25 x ^{7} y ^{8}}{x ^{8} y ^{3}}

1 - 3 i

\frac{3 + 7 i}{5 - 3 i}

(1 + 0.05)^{4}