What is ((x^2+9x+18)/(7x+42)}{\frac{x^2-9)/x} ?

The solution to ((x^2+9x+18)/(7x+42)}{\frac{x^2-9)/x} is x/(7(x-3))

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simplify ((x^2+9x+18)/(7x+42)}{\frac{x^2-9)/x}

simplify

\frac{\frac{x ^{2} + 9 x + 18}{7 x + 42}}{\frac{x ^{2} - 9}{x}}

\frac{x}{7 ( x - 3 )}

Solution steps

\frac{\frac{x ^{2} + 9 x + 18}{7 x + 42}}{\frac{x ^{2} - 9}{x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + 9 x + 18 ) x}{( 7 x + 42 ) ( x ^{2} - 9 )}

Cancel

\frac{( x ^{2} + 9 x + 18 ) x}{( 7 x + 42 ) ( x ^{2} - 9 )} : \frac{x}{7 ( x - 3 )}

= \frac{x}{7 ( x - 3 )}

(6 a^{2} - b)^{2}

(x + 15)^{2}

\frac{105}{2}

(\frac{4 8 ^{\frac{1}{4}}}{6 ^{\frac{1}{4}}})^{6}

5 \div 3 \frac{1}{3}

What is ((x^2+9x+18)/(7x+42)}{\frac{x^2-9)/x} ?
The solution to ((x^2+9x+18)/(7x+42)}{\frac{x^2-9)/x} is x/(7(x-3))