What is (x^2-5x+4)/(9x^2-36x) ?

The solution to (x^2-5x+4)/(9x^2-36x) is (x-1)/(9x)

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simplify (x^2-5x+4)/(9x^2-36x)

simplify

\frac{x ^{2} - 5 x + 4}{9 x ^{2} - 36 x}

\frac{x - 1}{9 x}

Solution steps

\frac{x ^{2} - 5 x + 4}{9 x ^{2} - 36 x}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{9 x ^{2} - 36 x}

Factor

9 x^{2} - 36 x : 9 x (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{9 x ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{x - 1}{9 x}

(7 x + 1)^{2}

8 \cdot (- 8)

\frac{( 2 x ^{4} + 4 x ^{3} - 5 x ^{2} + 2 x - 3 )}{( 2 x ^{2} + 1 )}

\frac{3 a + 2}{2} - \frac{2 a + 1}{2}

\frac{12}{24}

What is (x^2-5x+4)/(9x^2-36x) ?
The solution to (x^2-5x+4)/(9x^2-36x) is (x-1)/(9x)