What is (x-8)/(x^2-3x-40)*(x^2-25)/(x+9) ?

The solution to (x-8)/(x^2-3x-40)*(x^2-25)/(x+9) is (x-5)/(x+9)

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simplify (x-8)/(x^2-3x-40)*(x^2-25)/(x+9)

simplify

\frac{x - 8}{x ^{2} - 3 x - 40} \cdot \frac{x ^{2} - 25}{x + 9}

\frac{x - 5}{x + 9}

Solution steps

\frac{x - 8}{x ^{2} - 3 x - 40} \cdot \frac{x ^{2} - 25}{x + 9}

Cancel

\frac{x - 8}{x ^{2} - 3 x - 40} : \frac{1}{x + 5}

= \frac{1}{x + 5} \cdot \frac{x ^{2} - 25}{x + 9}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( x ^{2} - 25 )}{( x + 5 ) ( x + 9 )}

Apply rule:

1 \cdot a = a

1 \cdot (x^{2} - 25) = (x^{2} - 25)

= \frac{x ^{2} - 25}{( x + 5 ) ( x + 9 )}

Factor

x^{2} - 25 : (x + 5) (x - 5)

= \frac{( x + 5 ) ( x - 5 )}{( x + 5 ) ( x + 9 )}

Cancel the common factor:

x + 5

= \frac{x - 5}{x + 9}

(3 + 2 x - x^{2}) + (x^{2} + 8 x + 5)

lo g_{3} (324) - lo g_{3} (4)

- x + 2 z + x + 2 y

(2 x + 1) (2 x + 3)

\frac{6}{- 5}

What is (x-8)/(x^2-3x-40)*(x^2-25)/(x+9) ?
The solution to (x-8)/(x^2-3x-40)*(x^2-25)/(x+9) is (x-5)/(x+9)