What is (21x^3)/(7x^4+35x^3) ?

The solution to (21x^3)/(7x^4+35x^3) is 3/(x+5)

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simplify (21x^3)/(7x^4+35x^3)

simplify

\frac{21 x ^{3}}{7 x ^{4} + 35 x ^{3}}

\frac{3}{x + 5}

Solution steps

\frac{21 x ^{3}}{7 x ^{4} + 35 x ^{3}}

Factor

7 x^{4} + 35 x^{3} : 7 x^{3} (x + 5)

= \frac{21 x ^{3}}{7 x ^{3} ( x + 5 )}

Cancel the common factor:

x^{3}

= \frac{21}{7 ( x + 5 )}

Factor the number:

21 = 7 \cdot 3

= \frac{7 \cdot 3}{7 ( x + 5 )}

Cancel the common factor:

7

= \frac{3}{x + 5}

a^{2} - 2 a - 24

(2 y - 5)^{2}

\frac{1}{5} \times 3

\frac{4}{5} + \frac{3}{5}

\frac{125 x ^{7} y}{125 x ^{8} y ^{2}}