What is (6x+48)/(x^2-9x)*(x^2-81)/(x^2+17x+72) ?

The solution to (6x+48)/(x^2-9x)*(x^2-81)/(x^2+17x+72) is 6/x

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simplify (6x+48)/(x^2-9x)*(x^2-81)/(x^2+17x+72)

simplify

\frac{6 x + 48}{x ^{2} - 9 x} \cdot \frac{x ^{2} - 81}{x ^{2} + 17 x + 72}

\frac{6}{x}

Solution steps

\frac{6 x + 48}{x ^{2} - 9 x} \cdot \frac{x ^{2} - 81}{x ^{2} + 17 x + 72}

Cancel

\frac{x ^{2} - 81}{x ^{2} + 17 x + 72} : \frac{x - 9}{x + 8}

= \frac{6 x + 48}{x ^{2} - 9 x} \cdot \frac{x - 9}{x + 8}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 6 x + 48 ) ( x - 9 )}{( x ^{2} - 9 x ) ( x + 8 )}

Factor

6 x + 48 : 6 (x + 8)

= \frac{6 ( x + 8 ) ( x - 9 )}{( x ^{2} - 9 x ) ( x + 8 )}

Cancel the common factor:

x + 8

= \frac{6 ( x - 9 )}{x ^{2} - 9 x}

Factor

x^{2} - 9 x : x (x - 9)

= \frac{6 ( x - 9 )}{x ( x - 9 )}

Cancel the common factor:

x - 9

= \frac{6}{x}

(- 6) (- 2 - 42)

\frac{3 x + 1}{4 x + 3} + \frac{9 x ^{2}}{x - 5}

530

- 3^{2}

4 - (- 8)^{\frac{2}{3}}

What is (6x+48)/(x^2-9x)*(x^2-81)/(x^2+17x+72) ?
The solution to (6x+48)/(x^2-9x)*(x^2-81)/(x^2+17x+72) is 6/x