What is (-3(j^{-3}a^4)^{-3})/(3j^4a^8) ?

The solution to (-3(j^{-3}a^4)^{-3})/(3j^4a^8) is -(j^5)/(a^{20)}

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simplify (-3(j^{-3}a^4)^{-3})/(3j^4a^8)

simplify

\frac{- 3 ( j ^{- 3} a ^{4} ) ^{- 3}}{3 j ^{4} a ^{8}}

- \frac{j ^{5}}{a ^{20}}

Solution steps

\frac{- 3 ( j ^{- 3} a ^{4} ) ^{- 3}}{3 j ^{4} a ^{8}}

Cancel the common factor:

3

= \frac{- ( j ^{- 3} a ^{4} ) ^{- 3}}{j ^{4} a ^{8}}

Simplify

(j^{- 3} a^{4})^{- 3} : j^{9} \frac{1}{a ^{12}}

= \frac{- j ^{9} \frac{1}{a ^{12}}}{j ^{4} a ^{8}}

Simplify

\frac{j ^{9}}{j ^{4}} : j^{5}

= \frac{- j ^{5} \frac{1}{a ^{12}}}{a ^{8}}

Simplify

\frac{- j ^{5} \frac{1}{a ^{12}}}{a ^{8}} : - \frac{j ^{5}}{a ^{20}}

= - \frac{j ^{5}}{a ^{20}}

17 \frac{4}{9} - 12 \frac{2}{3}

(- 5 x^{2}) (2 x^{5})

e^{- 2 iπ}

(a^{5} - b^{5})^{2}

(- 2 i)^{4}

What is (-3(j^{-3}a^4)^{-3})/(3j^4a^8) ?
The solution to (-3(j^{-3}a^4)^{-3})/(3j^4a^8) is -(j^5)/(a^{20)}