What are the solutions to the equation 12x^2-6x+1=0 ?

The solutions to the equation 12x^2-6x+1=0 are x= 1/4+i(sqrt(3))/(12),x= 1/4-i(sqrt(3))/(12)

Find the zeros of 12x^2-6x+1=0

The zeros of 12x^2-6x+1=0 are x= 1/4+i(sqrt(3))/(12),x= 1/4-i(sqrt(3))/(12)

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12 x^{2} - 6 x + 1 = 0

x = \frac{1}{4} + i \frac{3}{12}, x = \frac{1}{4} - i \frac{3}{12}

Solution steps

12 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 12 \cdot 1}{2 \cdot 12}

Simplify

(- 6)^{2} - 4 \cdot 12 \cdot 1 : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 12}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 12}

x = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 12} : \frac{1}{4} + i \frac{3}{12}

x = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 12} : \frac{1}{4} - i \frac{3}{12}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{3}{12}, x = \frac{1}{4} - i \frac{3}{12}

3 h^{2} + 10 h + 3

2 (- 1) + 3

10 w + 4 w = - 84

7 m^{2} + 6 m - 1

5 + \frac{3}{4}

What are the solutions to the equation 12x^2-6x+1=0 ?
The solutions to the equation 12x^2-6x+1=0 are x= 1/4+i(sqrt(3))/(12),x= 1/4-i(sqrt(3))/(12)
Find the zeros of 12x^2-6x+1=0
The zeros of 12x^2-6x+1=0 are x= 1/4+i(sqrt(3))/(12),x= 1/4-i(sqrt(3))/(12)