What is (\frac{x+2)/(x-4)}{1/(3x-12)} ?

The solution to (\frac{x+2)/(x-4)}{1/(3x-12)} is 3x+6

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simplify (\frac{x+2)/(x-4)}{1/(3x-12)}

simplify

\frac{\frac{x + 2}{x - 4}}{\frac{1}{3 x - 12}}

3 x + 6

Solution steps

\frac{\frac{x + 2}{x - 4}}{\frac{1}{3 x - 12}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x + 2 ) ( 3 x - 12 )}{( x - 4 ) \cdot 1}

Apply rule:

a \cdot 1 = a

= \frac{( x + 2 ) ( 3 x - 12 )}{x - 4}

Cancel

\frac{( x + 2 ) ( 3 x - 12 )}{x - 4} : (x + 2) \cdot 3

= (x + 2) \cdot 3

Expand

(x + 2) \cdot 3 : 3 x + 6

= 3 x + 6

\frac{18}{40}

(5 x^{2} - 3 x - 2) + (6 x^{5} + 4 x - 2 x^{2} - 7)

3 x^{2} - 24 x - 27

\frac{1}{4} \cdot \frac{3}{5}

45 - 125 - 20

What is (\frac{x+2)/(x-4)}{1/(3x-12)} ?
The solution to (\frac{x+2)/(x-4)}{1/(3x-12)} is 3x+6