What is factor 12b^3-10b^2+48b-40 ?

The solution to factor 12b^3-10b^2+48b-40 is 2(6b-5)(b^2+4)

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factor 12b^3-10b^2+48b-40

factor

12 b^{3} - 10 b^{2} + 48 b - 40

2 (6 b - 5) (b^{2} + 4)

Solution steps

12 b^{3} - 10 b^{2} + 48 b - 40

Factor out common term

2 : 2 (6 b^{3} - 5 b^{2} + 24 b - 20)

= 2 (6 b^{3} - 5 b^{2} + 24 b - 20)

Factor

6 b^{3} - 5 b^{2} + 24 b - 20 : (6 b - 5) (b^{2} + 4)

= 2 (6 b - 5) (b^{2} + 4)

7 + i + 4 + 4

⎩ ⎨ ⎧ [(\frac{2}{3})^{2}]^{3} ⎭ ⎬ ⎫^{- 4}

36 - 4 x^{2}

\frac{- 1}{3}

x^{2} = - 18 x

What is factor 12b^3-10b^2+48b-40 ?
The solution to factor 12b^3-10b^2+48b-40 is 2(6b-5)(b^2+4)