What is (2/5)^{-3}x(3/7)^{-3} ?

The solution to (2/5)^{-3}x(3/7)^{-3} is (42875x)/(216)

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simplify (2/5)^{-3}x(3/7)^{-3}

simplify

(\frac{2}{5})^{- 3} x (\frac{3}{7})^{- 3}

\frac{42875 x}{216}

Solution steps

(\frac{2}{5})^{- 3} x (\frac{3}{7})^{- 3}

(\frac{2}{5})^{- 3} = \frac{125}{8}

= \frac{125}{8} x (\frac{3}{7})^{- 3}

(\frac{3}{7})^{- 3} = \frac{343}{27}

= \frac{125}{8} x \frac{343}{27}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{125 x \cdot 343}{8 \cdot 27}

Multiply the numbers:

125 \cdot 343 = 42875

= \frac{42875 x}{8 \cdot 27}

Multiply the numbers:

8 \cdot 27 = 216

= \frac{42875 x}{216}

4 - (8)^{\frac{2}{3}}

3 x + 2 x^{3}

\frac{( 2 x + 1 ) - 1}{2}

\frac{5}{2} - \frac{1}{4}

\frac{x + 9}{x - 1} \cdot \frac{x ^{2} - 7 x + 6}{x ^{2} + 3 x - 54}

What is (2/5)^{-3}x(3/7)^{-3} ?
The solution to (2/5)^{-3}x(3/7)^{-3} is (42875x)/(216)