What is ((2x^3+7x^2-6x-8))/((x+4)) ?

The solution to ((2x^3+7x^2-6x-8))/((x+4)) is 2x^2-x-2

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simplify ((2x^3+7x^2-6x-8))/((x+4))

simplify

\frac{( 2 x ^{3} + 7 x ^{2} - 6 x - 8 )}{( x + 4 )}

2 x^{2} - x - 2

Solution steps

\frac{2 x ^{3} + 7 x ^{2} - 6 x - 8}{x + 4}

Factor

2 x^{3} + 7 x^{2} - 6 x - 8 : (x + 4) (2 x^{2} - x - 2)

= \frac{( x + 4 ) ( 2 x ^{2} - x - 2 )}{x + 4}

Cancel the common factor:

x + 4

= 2 x^{2} - x - 2

lo g_{10} (\frac{4}{3})

\frac{6 ^{8}}{6 ^{3}}

\frac{2}{3 3}

- 50 - 3200

2 x^{3} + 5 x^{2} - 4 x - 3

What is ((2x^3+7x^2-6x-8))/((x+4)) ?
The solution to ((2x^3+7x^2-6x-8))/((x+4)) is 2x^2-x-2