What are the solutions to the equation 2x^2-2x-9=0 ?

The solutions to the equation 2x^2-2x-9=0 are x=(1+sqrt(19))/2 ,x=(1-sqrt(19))/2

Find the zeros of 2x^2-2x-9=0

The zeros of 2x^2-2x-9=0 are x=(1+sqrt(19))/2 ,x=(1-sqrt(19))/2

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2 x^{2} - 2 x - 9 = 0

x = \frac{1 + 19}{2}, x = \frac{1 - 19}{2}

Solution steps

2 x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 9) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 2} : \frac{1 + 19}{2}

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 2} : \frac{1 - 19}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 19}{2}, x = \frac{1 - 19}{2}

1.0 5^{2}

a^{2} - x y - a x + a y

4 u^{3} + 22 u^{2} - 12 u

\frac{2}{x} < 4

k^{2} (a + 2) - 9 a - 18

What are the solutions to the equation 2x^2-2x-9=0 ?
The solutions to the equation 2x^2-2x-9=0 are x=(1+sqrt(19))/2 ,x=(1-sqrt(19))/2
Find the zeros of 2x^2-2x-9=0
The zeros of 2x^2-2x-9=0 are x=(1+sqrt(19))/2 ,x=(1-sqrt(19))/2