What is (y^2-2y^5+3y)-(12y-7y^2+9y^5) ?

The solution to (y^2-2y^5+3y)-(12y-7y^2+9y^5) is -11y^5+8y^2-9y

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simplify (y^2-2y^5+3y)-(12y-7y^2+9y^5)

simplify

(y^{2} - 2 y^{5} + 3 y) - (12 y - 7 y^{2} + 9 y^{5})

- 11 y^{5} + 8 y^{2} - 9 y

Solution steps

(y^{2} - 2 y^{5} + 3 y) - (12 y - 7 y^{2} + 9 y^{5})

Apply rule:

(a) = a

(y^{2} - 2 y^{5} + 3 y) = y^{2} - 2 y^{5} + 3 y

= y^{2} - 2 y^{5} + 3 y - (12 y - 7 y^{2} + 9 y^{5})

Apply the distributive law:

- (a - b) = - a + b

- (12 y - 7 y^{2} + 9 y^{5}) = - 12 y + 7 y^{2} - 9 y^{5}

= y^{2} - 2 y^{5} + 3 y - 12 y + 7 y^{2} - 9 y^{5}

Add similar elements:

3 y - 12 y = - 9 y

= y^{2} - 2 y^{5} - 9 y + 7 y^{2} - 9 y^{5}

Group like terms

= - 2 y^{5} - 9 y^{5} + y^{2} + 7 y^{2} - 9 y

Add similar elements:

- 2 y^{5} - 9 y^{5} = - 11 y^{5}

= - 11 y^{5} + y^{2} + 7 y^{2} - 9 y

Add similar elements:

y^{2} + 7 y^{2} = 8 y^{2}

= - 11 y^{5} + 8 y^{2} - 9 y

\frac{25 x ^{7} y ^{3}}{x y ^{2}}

\frac{( \frac{1}{x} )}{x}

\frac{x}{x - 1} - \frac{x - 2}{3 x}

(- 1 - x)^{3}

\frac{3 x}{x ^{3}}

What is (y^2-2y^5+3y)-(12y-7y^2+9y^5) ?
The solution to (y^2-2y^5+3y)-(12y-7y^2+9y^5) is -11y^5+8y^2-9y