What is (3x^3+5x^2-9x-2)-(2x^3+3x^2-x-3) ?

The solution to (3x^3+5x^2-9x-2)-(2x^3+3x^2-x-3) is x^3+2x^2-8x+1

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simplify (3x^3+5x^2-9x-2)-(2x^3+3x^2-x-3)

simplify

(3 x^{3} + 5 x^{2} - 9 x - 2) - (2 x^{3} + 3 x^{2} - x - 3)

x^{3} + 2 x^{2} - 8 x + 1

Solution steps

(3 x^{3} + 5 x^{2} - 9 x - 2) - (2 x^{3} + 3 x^{2} - x - 3)

Apply rule:

(a) = a

(3 x^{3} + 5 x^{2} - 9 x - 2) = 3 x^{3} + 5 x^{2} - 9 x - 2

= 3 x^{3} + 5 x^{2} - 9 x - 2 - (2 x^{3} + 3 x^{2} - x - 3)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{3} + 3 x^{2} - x - 3) = - 2 x^{3} - 3 x^{2} + x + 3

= 3 x^{3} + 5 x^{2} - 9 x - 2 - 2 x^{3} - 3 x^{2} + x + 3

Group like terms

= 3 x^{3} - 2 x^{3} + 5 x^{2} - 3 x^{2} - 9 x + x - 2 + 3

Add similar elements:

3 x^{3} - 2 x^{3} = x^{3}

= x^{3} + 5 x^{2} - 3 x^{2} - 9 x + x - 2 + 3

Add similar elements:

5 x^{2} - 3 x^{2} = 2 x^{2}

= x^{3} + 2 x^{2} - 9 x + x - 2 + 3

Add similar elements:

- 9 x + x = - 8 x

= x^{3} + 2 x^{2} - 8 x - 2 + 3

Add the numbers:

- 2 + 3 = 1

= x^{3} + 2 x^{2} - 8 x + 1

(\frac{- 1}{2})^{3}

\frac{x - 6}{x ^{2} - 36}

7 + (- 1)

(a + b + c)^{4}

(\frac{3}{5} + \frac{5}{2} i)^{2}

What is (3x^3+5x^2-9x-2)-(2x^3+3x^2-x-3) ?
The solution to (3x^3+5x^2-9x-2)-(2x^3+3x^2-x-3) is x^3+2x^2-8x+1