What are the solutions to the equation 16x^2+7=70 ?

The solutions to the equation 16x^2+7=70 are x=(3sqrt(7))/4 ,x=-(3sqrt(7))/4

Find the zeros of 16x^2+7=70

The zeros of 16x^2+7=70 are x=(3sqrt(7))/4 ,x=-(3sqrt(7))/4

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16 x^{2} + 7 = 70

x = \frac{3 7}{4}, x = - \frac{3 7}{4}

Solution steps

16 x^{2} + 7 = 70

Move

7

to the right side

16 x^{2} = 63

Divide both sides by

16

x^{2} = \frac{63}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{63}{16}, x = - \frac{63}{16}

\frac{63}{16} = \frac{3 7}{4}

- \frac{63}{16} = - \frac{3 7}{4}

x = \frac{3 7}{4}, x = - \frac{3 7}{4}

14 + 12 w = - 16 + 9 w

x^{2} - 1 = 3

2 x + 1 \leq 0

\frac{x}{4} = x

15 y^{3} + 20 y^{2} - 5 y

What are the solutions to the equation 16x^2+7=70 ?
The solutions to the equation 16x^2+7=70 are x=(3sqrt(7))/4 ,x=-(3sqrt(7))/4
Find the zeros of 16x^2+7=70
The zeros of 16x^2+7=70 are x=(3sqrt(7))/4 ,x=-(3sqrt(7))/4