What is expand (x^2+2x-3)(3x^2-2x+4) ?

The solution to expand (x^2+2x-3)(3x^2-2x+4) is 3x^4+4x^3-9x^2+14x-12

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expand (x^2+2x-3)(3x^2-2x+4)

expand

(x^{2} + 2 x - 3) (3 x^{2} - 2 x + 4)

3 x^{4} + 4 x^{3} - 9 x^{2} + 14 x - 12

Solution steps

(x^{2} + 2 x - 3) (3 x^{2} - 2 x + 4)

Distribute parentheses

= x^{2} \cdot 3 x^{2} + x^{2} (- 2 x) + x^{2} \cdot 4 + 2 x \cdot 3 x^{2} + 2 x (- 2 x) + 2 x \cdot 4 - 3 \cdot 3 x^{2} - 3 (- 2 x) - 3 \cdot 4

Simplify

x^{2} \cdot 3 x^{2} + x^{2} (- 2 x) + x^{2} \cdot 4 + 2 x \cdot 3 x^{2} + 2 x (- 2 x) + 2 x \cdot 4 - 3 \cdot 3 x^{2} - 3 (- 2 x) - 3 \cdot 4 : 3 x^{4} + 4 x^{3} - 9 x^{2} + 14 x - 12

= 3 x^{4} + 4 x^{3} - 9 x^{2} + 14 x - 12

(0)^{3}

\frac{60}{9}

(- 2 sin (2 t))^{2}

\frac{30 x ^{3} y}{20 x ^{5} y ^{2}}

1 0^{- 4.9}

What is expand (x^2+2x-3)(3x^2-2x+4) ?
The solution to expand (x^2+2x-3)(3x^2-2x+4) is 3x^4+4x^3-9x^2+14x-12