What is (x^2-4)/(x^2+3x-10) ?

The solution to (x^2-4)/(x^2+3x-10) is (x+2)/(x+5)

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simplify (x^2-4)/(x^2+3x-10)

simplify

\frac{x ^{2} - 4}{x ^{2} + 3 x - 10}

\frac{x + 2}{x + 5}

Solution steps

\frac{x ^{2} - 4}{x ^{2} + 3 x - 10}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{x ^{2} + 3 x - 10}

Factor

x^{2} + 3 x - 10 : (x - 2) (x + 5)

= \frac{( x + 2 ) ( x - 2 )}{( x - 2 ) ( x + 5 )}

Cancel the common factor:

x - 2

= \frac{x + 2}{x + 5}

\frac{9}{15 x} + \frac{2}{15 x}

\frac{\frac{4}{3} + \frac{7}{2} + \frac{1}{3}}{\frac{11}{4}}

(a c) (- 4 a^{3} b)

1 + 3.3 lo g_{10} (30)

\frac{x - 2}{4 x ^{3}} \cdot \frac{x ^{2} - 1}{x ^{2} - x - 2}

What is (x^2-4)/(x^2+3x-10) ?
The solution to (x^2-4)/(x^2+3x-10) is (x+2)/(x+5)