What is 16m^6-2m^3n^2+(n^4)/(16) ?

The solution to 16m^6-2m^3n^2+(n^4)/(16) is (256m^6-32m^3n^2+n^4)/(16)

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simplify 16m^6-2m^3n^2+(n^4)/(16)

simplify

16 m^{6} - 2 m^{3} n^{2} + \frac{n ^{4}}{16}

\frac{256 m ^{6} - 32 m ^{3} n ^{2} + n ^{4}}{16}

Solution steps

16 m^{6} - 2 m^{3} n^{2} + \frac{n ^{4}}{16}

Convert

16 m^{6}

to fraction

: \frac{256 m ^{6}}{16}

Convert

2 m^{3} n^{2}

to fraction

: \frac{32 m ^{3} n ^{2}}{16}

= \frac{256 m ^{6}}{16} - \frac{32 m ^{3} n ^{2}}{16} + \frac{n ^{4}}{16}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{256 m ^{6} - 32 m ^{3} n ^{2} + n ^{4}}{16}

\frac{5}{m - 3} - \frac{1}{3 - m}

(6 x - 3)^{2}

\frac{10}{3} - 3

sin (x) (- sin (x))

\frac{1}{0}

What is 16m^6-2m^3n^2+(n^4)/(16) ?
The solution to 16m^6-2m^3n^2+(n^4)/(16) is (256m^6-32m^3n^2+n^4)/(16)