What are the solutions to the equation 4x^2+1=0 ?

The solutions to the equation 4x^2+1=0 are x= 1/2 i,x=-1/2 i

Find the zeros of 4x^2+1=0

The zeros of 4x^2+1=0 are x= 1/2 i,x=-1/2 i

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4 x^{2} + 1 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

4 x^{2} + 1 = 0

Move

1

to the right side

4 x^{2} = - 1

Divide both sides by

4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

∣ x - 1 ∣ \leq 2 (x - 1)

4 x - \frac{1}{3} (15 x - 3 (- 1 + 2 x)) = \frac{3}{2} (9 - x - 6)

2 x - 9 > 8 x - 21

- 6 x > - 10

(27 \cdot 64)^{\frac{2}{3}}

What are the solutions to the equation 4x^2+1=0 ?
The solutions to the equation 4x^2+1=0 are x= 1/2 i,x=-1/2 i
Find the zeros of 4x^2+1=0
The zeros of 4x^2+1=0 are x= 1/2 i,x=-1/2 i