What is factor 243-32b^5 ?

The solution to factor 243-32b^5 is -(2b-3)(16b^4+24b^3+36b^2+54b+81)

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factor 243-32b^5

factor

243 - 32 b^{5}

- (2 b - 3) (16 b^{4} + 24 b^{3} + 36 b^{2} + 54 b + 81)

Solution steps

243 - 32 b^{5}

Write in the standard form

= - 32 b^{5} + 243

Factor out

- 1 : - (32 b^{5} - 243)

= - (32 b^{5} - 243)

Factor

32 b^{5} - 243 : (2 b - 3) (2^{4} b^{4} + 3 \cdot 2^{3} b^{3} + 3^{2} \cdot 2^{2} b^{2} + 3^{3} \cdot 2 b + 3^{4})

= - (2 b - 3) (2^{4} b^{4} + 3 \cdot 2^{3} b^{3} + 3^{2} \cdot 2^{2} b^{2} + 3^{3} \cdot 2 b + 3^{4})

Simplify

- (2 b - 3) (2^{4} b^{4} + 3 \cdot 2^{3} b^{3} + 3^{2} \cdot 2^{2} b^{2} + 3^{3} \cdot 2 b + 3^{4}) : - (2 b - 3) (16 b^{4} + 24 b^{3} + 36 b^{2} + 54 b + 81)

= - (2 b - 3) (16 b^{4} + 24 b^{3} + 36 b^{2} + 54 b + 81)

7 \cdot (- 1)

(5 x - 4) (5 x - 2)

\frac{2 x ^{4} - 10 x ^{3}}{6 x}

(1 - t)^{3}

- 14 + 6

What is factor 243-32b^5 ?
The solution to factor 243-32b^5 is -(2b-3)(16b^4+24b^3+36b^2+54b+81)