What is x/(3x^2y)+(x+1)/(6xy^2)-3/(9xy) ?

The solution to x/(3x^2y)+(x+1)/(6xy^2)-3/(9xy) is (x+1)/(6xy^2)

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simplify x/(3x^2y)+(x+1)/(6xy^2)-3/(9xy)

simplify

\frac{x}{3 x ^{2} y} + \frac{x + 1}{6 x y ^{2}} - \frac{3}{9 x y}

\frac{x + 1}{6 x y ^{2}}

Solution steps

\frac{x}{3 x ^{2} y} + \frac{x + 1}{6 x y ^{2}} - \frac{3}{9 x y}

Simplify

\frac{x}{x ^{2}} : \frac{1}{x}

= \frac{1}{3 x y} + \frac{x + 1}{6 x y ^{2}} - \frac{3}{9 x y}

Cancel

\frac{3}{9} : \frac{1}{3}

= \frac{1}{3 x y} + \frac{x + 1}{6 x y ^{2}} - \frac{1}{3 x y}

Group like terms

= \frac{1}{3 x y} - \frac{1}{3 x y} + \frac{x + 1}{6 x y ^{2}}

Add similar elements:

\frac{1}{3 x y} - \frac{1}{3 x y} = 0

= \frac{x + 1}{6 x y ^{2}}

\frac{\frac{1}{2} x ^{2}}{\frac{2}{3}}

lo g_{10} (5 \cdot 3)

\frac{2}{1 + \frac{2}{1 + \frac{2}{x}}}

5 (- 3 x)

\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}

What is x/(3x^2y)+(x+1)/(6xy^2)-3/(9xy) ?
The solution to x/(3x^2y)+(x+1)/(6xy^2)-3/(9xy) is (x+1)/(6xy^2)