What are the solutions to the equation (x-6)(x+7)=0 ?

The solutions to the equation (x-6)(x+7)=0 are x=6,x=-7

Find the zeros of (x-6)(x+7)=0

The zeros of (x-6)(x+7)=0 are x=6,x=-7

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(x - 6) (x + 7) = 0

x = 6, x = - 7

Solution steps

(x - 6) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 7 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 6, x = - 7

(\frac{2}{3})^{4}

2 ∣ 4 x - 1 ∣ + 5 = 15

x^{3} + 5 x^{2} - 25 x - 125

x (x + 5) = 24

2 x - 17 = 2

What are the solutions to the equation (x-6)(x+7)=0 ?
The solutions to the equation (x-6)(x+7)=0 are x=6,x=-7
Find the zeros of (x-6)(x+7)=0
The zeros of (x-6)(x+7)=0 are x=6,x=-7