What is ((2x+1)!)/((2x+3)!) ?

The solution to ((2x+1)!)/((2x+3)!) is 1/((2x+2)(2x+3))

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simplify ((2x+1)!)/((2x+3)!)

simplify

\frac{( 2 x + 1 ) !}{( 2 x + 3 ) !}

\frac{1}{( 2 x + 2 ) ( 2 x + 3 )}

Solution steps

\frac{( 2 x + 1 ) !}{( 2 x + 3 ) !}

Cancel the factorials:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( 2 x + 1 ) !}{( 2 x + 3 ) !} = \frac{1}{( 2 x + 2 ) ( 2 x + 3 )}

= \frac{1}{( 2 x + 2 ) ( 2 x + 3 )}

4 x^{5} + 20 x^{4} - 3 x^{2} - 14 x + 5

(- 1 - 3 i)^{2}

(9 - a) (9 + a)

lo g_{12} (89.5)

\frac{1}{4} \cdot (- 1)

What is ((2x+1)!)/((2x+3)!) ?
The solution to ((2x+1)!)/((2x+3)!) is 1/((2x+2)(2x+3))