What is (8-2i^4)+(3-7i^8)-(4+i^9) ?

The solution to (8-2i^4)+(3-7i^8)-(4+i^9) is -2-i

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simplify (8-2i^4)+(3-7i^8)-(4+i^9)

simplify

(8 - 2 i^{4}) + (3 - 7 i^{8}) - (4 + i^{9})

- 2 - i

Solution steps

(8 - 2 i^{4}) + (3 - 7 i^{8}) - (4 + i^{9})

Simplify

(8 - 2 i^{4}) + (3 - 7 i^{8}) - (4 + i^{9}) : 8 - 2 i^{4} + 3 - 7 i^{8} - (4 + i^{9})

= 8 - 2 i^{4} + 3 - 7 i^{8} - (4 + i^{9})

Group like terms

= - (4 + i^{9}) - 7 i^{8} - 2 i^{4} + 8 + 3

Add the numbers:

8 + 3 = 11

= - (4 + i^{9}) - 7 i^{8} - 2 i^{4} + 11

- (4 + i^{9}) = - 4 - i

7 i^{8} = 7

2 i^{4} = 2

= - 4 - i - 7 - 2 + 11

Group like terms

= - i - 4 - 7 - 2 + 11

Add the numbers:

- 4 - 7 - 2 + 11 = - 2

= - i - 2

Rewrite in standard complex form:

- 2 - i

= - 2 - i

(x + 4)^{2} - (x - 4)^{2}

\frac{x ^{3}}{3 x}

(5 a^{2} x - 3 b^{2} y)^{2}

4 x^{3} + 7 x^{2} + 4 x + 7

(k - 6)^{2}

What is (8-2i^4)+(3-7i^8)-(4+i^9) ?
The solution to (8-2i^4)+(3-7i^8)-(4+i^9) is -2-i