What is (4x^4+8x^3)/(x^2-2x-8) ?

The solution to (4x^4+8x^3)/(x^2-2x-8) is (4x^3)/(x-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4x^4+8x^3)/(x^2-2x-8)

simplify

\frac{4 x ^{4} + 8 x ^{3}}{x ^{2} - 2 x - 8}

\frac{4 x ^{3}}{x - 4}

Solution steps

\frac{4 x ^{4} + 8 x ^{3}}{x ^{2} - 2 x - 8}

Factor

4 x^{4} + 8 x^{3} : 4 x^{3} (x + 2)

= \frac{4 x ^{3} ( x + 2 )}{x ^{2} - 2 x - 8}

Factor

x^{2} - 2 x - 8 : (x + 2) (x - 4)

= \frac{4 x ^{3} ( x + 2 )}{( x + 2 ) ( x - 4 )}

Cancel the common factor:

x + 2

= \frac{4 x ^{3}}{x - 4}

- 3 (x + 2)

\frac{8}{5 x y} - \frac{6}{10 x y}

x^{2} + 4 x - y^{2} + 4

\frac{18}{90}

What is (4x^4+8x^3)/(x^2-2x-8) ?
The solution to (4x^4+8x^3)/(x^2-2x-8) is (4x^3)/(x-4)