What is (x^2+2x-5)-(3x^2-4x+7) ?

The solution to (x^2+2x-5)-(3x^2-4x+7) is -2x^2+6x-12

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simplify (x^2+2x-5)-(3x^2-4x+7)

simplify

(x^{2} + 2 x - 5) - (3 x^{2} - 4 x + 7)

- 2 x^{2} + 6 x - 12

Solution steps

(x^{2} + 2 x - 5) - (3 x^{2} - 4 x + 7)

Apply rule:

(a) = a

(x^{2} + 2 x - 5) = x^{2} + 2 x - 5

= x^{2} + 2 x - 5 - (3 x^{2} - 4 x + 7)

Apply the distributive law:

- (a - b) = - a + b

- (3 x^{2} - 4 x + 7) = - 3 x^{2} + 4 x - 7

= x^{2} + 2 x - 5 - 3 x^{2} + 4 x - 7

Group like terms

= x^{2} - 3 x^{2} + 2 x + 4 x - 5 - 7

Add similar elements:

x^{2} - 3 x^{2} = - 2 x^{2}

= - 2 x^{2} + 2 x + 4 x - 5 - 7

Add similar elements:

2 x + 4 x = 6 x

= - 2 x^{2} + 6 x - 5 - 7

Subtract the numbers:

- 5 - 7 = - 12

= - 2 x^{2} + 6 x - 12

\frac{cos ( θ )}{sin ( θ )} + \frac{sin ( θ )}{cos ( θ )}

9. 8^{2}

\frac{10}{1 + 2 i}

3 x^{3} - x^{2} \times (- 2) x

6 \frac{1}{4} - 3 \frac{5}{8}

What is (x^2+2x-5)-(3x^2-4x+7) ?
The solution to (x^2+2x-5)-(3x^2-4x+7) is -2x^2+6x-12