What is factor x^4-2x^3-7x^2+8x+12 ?

The solution to factor x^4-2x^3-7x^2+8x+12 is (x+1)(x-3)(x+2)(x-2)

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factor x^4-2x^3-7x^2+8x+12

factor

x^{4} - 2 x^{3} - 7 x^{2} + 8 x + 12

(x + 1) (x - 3) (x + 2) (x - 2)

Solution steps

x^{4} - 2 x^{3} - 7 x^{2} + 8 x + 12

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 2 x ^{3} - 7 x ^{2} + 8 x + 12}{x + 1}

\frac{x ^{4} - 2 x ^{3} - 7 x ^{2} + 8 x + 12}{x + 1} = x^{3} - 3 x^{2} - 4 x + 12

= (x + 1) (x^{3} - 3 x^{2} - 4 x + 12)

Factor

x^{3} - 3 x^{2} - 4 x + 12 : (x - 3) (x + 2) (x - 2)

= (x + 1) (x - 3) (x + 2) (x - 2)

0 - 12

\frac{\frac{1}{2}}{\frac{3}{2}}

12 + 5

(\frac{5}{6})^{- 3}

- 9 + - 12 - 81 + - 27

What is factor x^4-2x^3-7x^2+8x+12 ?
The solution to factor x^4-2x^3-7x^2+8x+12 is (x+1)(x-3)(x+2)(x-2)