What is (4(x^2-1))/(12(x+2)(x-1)) ?

The solution to (4(x^2-1))/(12(x+2)(x-1)) is (x+1)/(3(x+2))

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simplify (4(x^2-1))/(12(x+2)(x-1))

simplify

\frac{4 ( x ^{2} - 1 )}{12 ( x + 2 ) ( x - 1 )}

\frac{x + 1}{3 ( x + 2 )}

Solution steps

\frac{4 ( x ^{2} - 1 )}{12 ( x + 2 ) ( x - 1 )}

Factor the number:

12 = 4 \cdot 3

= \frac{4 ( x ^{2} - 1 )}{4 \cdot 3 ( x + 2 ) ( x - 1 )}

Cancel the common factor:

4

= \frac{x ^{2} - 1}{3 ( x + 2 ) ( x - 1 )}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{3 ( x + 2 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 1}{3 ( x + 2 )}

(x^{2} - 4)^{2} - 4

4 (x - 4)

(\frac{2 ab}{3 c ^{3}})^{2}

\frac{3}{4} \div \frac{4}{3}

(- 9 - 42) (5 - 6)

What is (4(x^2-1))/(12(x+2)(x-1)) ?
The solution to (4(x^2-1))/(12(x+2)(x-1)) is (x+1)/(3(x+2))