What is (5x+x^2-4)-(4x-x^2+6) ?

The solution to (5x+x^2-4)-(4x-x^2+6) is 2x^2+x-10

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simplify (5x+x^2-4)-(4x-x^2+6)

simplify

(5 x + x^{2} - 4) - (4 x - x^{2} + 6)

2 x^{2} + x - 10

Solution steps

(5 x + x^{2} - 4) - (4 x - x^{2} + 6)

Apply rule:

(a) = a

(5 x + x^{2} - 4) = 5 x + x^{2} - 4

= 5 x + x^{2} - 4 - (4 x - x^{2} + 6)

Apply the distributive law:

- (a - b) = - a + b

- (4 x - x^{2} + 6) = - 4 x + x^{2} - 6

= 5 x + x^{2} - 4 - 4 x + x^{2} - 6

Group like terms

= x^{2} + x^{2} + 5 x - 4 x - 4 - 6

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

= 2 x^{2} + 5 x - 4 x - 4 - 6

Add similar elements:

5 x - 4 x = x

= 2 x^{2} + x - 4 - 6

Subtract the numbers:

- 4 - 6 = - 10

= 2 x^{2} + x - 10

\frac{x}{x ^{2} - x - 6} - \frac{1}{x + 2} - \frac{2}{x - 3}

\frac{125}{25}

x^{3} - 7 x^{2} - 14 x + 98

798 - 732

- \frac{4}{2 ( 1 )}

What is (5x+x^2-4)-(4x-x^2+6) ?
The solution to (5x+x^2-4)-(4x-x^2+6) is 2x^2+x-10