What is factor x^4+5x^3+5x^2-5x-6 ?

The solution to factor x^4+5x^3+5x^2-5x-6 is (x-1)(x+1)(x+2)(x+3)

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factor x^4+5x^3+5x^2-5x-6

factor

x^{4} + 5 x^{3} + 5 x^{2} - 5 x - 6

(x - 1) (x + 1) (x + 2) (x + 3)

Solution steps

x^{4} + 5 x^{3} + 5 x^{2} - 5 x - 6

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 5 x ^{3} + 5 x ^{2} - 5 x - 6}{x - 1}

\frac{x ^{4} + 5 x ^{3} + 5 x ^{2} - 5 x - 6}{x - 1} = x^{3} + 6 x^{2} + 11 x + 6

= (x - 1) (x^{3} + 6 x^{2} + 11 x + 6)

Factor

x^{3} + 6 x^{2} + 11 x + 6 : (x + 1) (x + 2) (x + 3)

= (x - 1) (x + 1) (x + 2) (x + 3)

lo g_{0.5} (0.5)

\frac{34}{4}

\frac{\frac{4}{5} - \frac{2}{5}}{\frac{5}{10} + \frac{4}{10}}

\frac{( 6 b ^{3} + 18 b - 27 b ^{2} )}{3 b}

- 4 \times 1

What is factor x^4+5x^3+5x^2-5x-6 ?
The solution to factor x^4+5x^3+5x^2-5x-6 is (x-1)(x+1)(x+2)(x+3)