What is (x^2-9)/(x^2-2x-3) ?

The solution to (x^2-9)/(x^2-2x-3) is (x+3)/(x+1)

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simplify (x^2-9)/(x^2-2x-3)

simplify

\frac{x ^{2} - 9}{x ^{2} - 2 x - 3}

\frac{x + 3}{x + 1}

Solution steps

\frac{x ^{2} - 9}{x ^{2} - 2 x - 3}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} - 2 x - 3}

Factor

x^{2} - 2 x - 3 : (x + 1) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{( x + 1 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x + 1}

\frac{x ^{2} + 2 x - 15}{x - 3}

8 \cdot (- 2)

\frac{9}{8 x} + \frac{8}{5 x}

5 x^{2} + 3 x^{2}