What is (ab^2-a^2b)/(ab)*(a^2b^2)/(a-b) ?

The solution to (ab^2-a^2b)/(ab)*(a^2b^2)/(a-b) is -a^2b^2

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simplify (ab^2-a^2b)/(ab)*(a^2b^2)/(a-b)

simplify

\frac{a b ^{2} - a ^{2} b}{ab} \cdot \frac{a ^{2} b ^{2}}{a - b}

- a^{2} b^{2}

Solution steps

\frac{a b ^{2} - a ^{2} b}{ab} \cdot \frac{a ^{2} b ^{2}}{a - b}

Cancel

\frac{a b ^{2} - a ^{2} b}{ab} : b - a

= (b - a) \frac{a ^{2} b ^{2}}{a - b}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( b - a ) a ^{2} b ^{2}}{a - b}

b - a = - (a - b)

= \frac{- ( a - b ) a ^{2} b ^{2}}{a - b}

Cancel the common factor:

a - b

= - a^{2} b^{2}

6 x^{2} - x^{2}

360000

7 \times (- 4)

\frac{( x ^{2} - 4 )}{( x + 2 )}

(3 x - 2 y + 1)^{2}

What is (ab^2-a^2b)/(ab)*(a^2b^2)/(a-b) ?
The solution to (ab^2-a^2b)/(ab)*(a^2b^2)/(a-b) is -a^2b^2