What is (32x^{30}y^{-40})^{-2/5} ?

The solution to (32x^{30}y^{-40})^{-2/5} is (y^{16})/(4x^{12)}

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simplify (32x^{30}y^{-40})^{-2/5}

simplify

(32 x^{30} y^{- 40})^{- \frac{2}{5}}

\frac{y ^{16}}{4 x ^{12}}

Solution steps

(32 x^{30} y^{- 40})^{- \frac{2}{5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(32 x^{30} y^{- 40})^{- \frac{2}{5}} = \frac{1}{( 32 x ^{30} y ^{- 40} ) ^{\frac{2}{5}}}

= \frac{1}{( 32 x ^{30} y ^{- 40} ) ^{\frac{2}{5}}}

Simplify

(32 x^{30} y^{- 40})^{\frac{2}{5}} : \frac{4 x ^{12}}{y ^{16}}

= \frac{1}{\frac{4 x ^{12}}{y ^{16}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{16}}{4 x ^{12}}

lo g_{8} (512) + lo g_{512} (8)

\frac{12 x + 36}{x ^{2} - 4 x - 21}

\frac{1}{2} \cdot \frac{2}{6}

\frac{1}{4} \div 1 \frac{1}{8}

0. 8^{10}

What is (32x^{30}y^{-40})^{-2/5} ?
The solution to (32x^{30}y^{-40})^{-2/5} is (y^{16})/(4x^{12)}