What is expand (x+2)(x+1)(x-1)(x-2) ?

The solution to expand (x+2)(x+1)(x-1)(x-2) is x^4-5x^2+4

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expand (x+2)(x+1)(x-1)(x-2)

expand

(x + 2) (x + 1) (x - 1) (x - 2)

x^{4} - 5 x^{2} + 4

Solution steps

(x + 2) (x + 1) (x - 1) (x - 2)

Expand

(x + 2) (x + 1) (x - 1) (x - 2) : (x^{2} - 4) (x + 1) (x - 1)

= (x^{2} - 4) (x + 1) (x - 1)

Apply Difference of Two Squares

(x + 1) (x - 1) : x^{2} - 1

= (x^{2} - 4) (x^{2} - 1)

Apply FOIL method

(x^{2} - 4) (x^{2} - 1) : x^{4} - 5 x^{2} + 4

= x^{4} - 5 x^{2} + 4

\frac{9}{- 1}

\frac{x ^{2} + 3 x + 2}{x ^{2} - x - 2}

- i (i)

(7^{6} \cdot 7)^{- 4} \cdot (\frac{7 ^{14}}{4 9 ^{0}})^{2}

(x + 2)^{9}

What is expand (x+2)(x+1)(x-1)(x-2) ?
The solution to expand (x+2)(x+1)(x-1)(x-2) is x^4-5x^2+4