What is ((4z^{-2}x^3)^2)/(2z^5x^2) ?

The solution to ((4z^{-2}x^3)^2)/(2z^5x^2) is (8x^4)/(z^9)

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simplify ((4z^{-2}x^3)^2)/(2z^5x^2)

simplify

\frac{( 4 z ^{- 2} x ^{3} ) ^{2}}{2 z ^{5} x ^{2}}

\frac{8 x ^{4}}{z ^{9}}

Solution steps

\frac{( 4 z ^{- 2} x ^{3} ) ^{2}}{2 z ^{5} x ^{2}}

Simplify

(4 z^{- 2} x^{3})^{2} : 4^{2} \cdot \frac{1}{z ^{4}} x^{6}

= \frac{4 ^{2} \cdot \frac{1}{z ^{4}} x ^{6}}{2 z ^{5} x ^{2}}

Factor

4^{2} : 2^{4}

= \frac{2 ^{4} \cdot \frac{1}{z ^{4}} x ^{6}}{2 z ^{5} x ^{2}}

\frac{2 ^{4}}{2} = 2^{3}

= \frac{2 ^{3} \cdot \frac{1}{z ^{4}} x ^{6}}{z ^{5} x ^{2}}

Simplify

\frac{x ^{6}}{x ^{2}} : x^{4}

= \frac{2 ^{3} \cdot \frac{1}{z ^{4}} x ^{4}}{z ^{5}}

Simplify

\frac{2 ^{3} \cdot \frac{1}{z ^{4}} x ^{4}}{z ^{5}} : \frac{8 x ^{4}}{z ^{9}}

= \frac{8 x ^{4}}{z ^{9}}

1 + 1

9 \frac{2}{3}

(5 y - 4)^{2}

81 x^{2} - 4

4 x^{2} + 16 x - 4

What is ((4z^{-2}x^3)^2)/(2z^5x^2) ?
The solution to ((4z^{-2}x^3)^2)/(2z^5x^2) is (8x^4)/(z^9)